PRACTICE WORKSHEETS

BODMAS WORKSHEET LEVEL1

BODMAS WORKSHEET LEVEL2 

BODMAS WORKSHEET LEVEL3

BODMAS WORKSHEET STD 6th 

BODMAS WORKSHEET STD 7th

RULE OF SIGN ADDITION WORKSHEET

What is BODMAS?| VBODMAS rules and order of operations | how question is solved using BODMAS ?| BODMAS examples

 What is BODMAS?

The BODMAS is an acronym to help students remember the orders of mathematical operations like we generally give a name to something just to remember it for longer time.

VBODMAS  stands for -->

                  V - Vinculum

                  B - Brackets

                  O - Order(order includes powers,percentage,parts"of" etc)

                  D - Division

                  M - Multiplication

                  A - Addition

                  S - Subtraction

**NOTE:- we will learn about Vinculum once we understand other parts of it.(only BODMAS).

whenever we have to perform some mathematical operation involving combination of many operators we use BODMAS method to simply our problem.

according to this method we have to solve the "bracket" first den solve all the "indices then do "division/multiplication" and finally "addition/subtraction'

Note: here the rank of (division and multiplication) is equal also the rank of (addition and subtraction)is equal.

now what is mean by equal rank, let us understand with an example

       ex:- 2+3-1=?

here in this sum we have to perform two mathematical operations

lets we first do addition - step1           2+3=5

now in the result of step1 i.e;   subtract 1

                       step2            5-1=4   --answer1

 in this step perform subtraction first

                        step1            3-1=2   

now in result of step1 i.e; 2, add 2

                        step2            2+2=4   --answer2

here if we look at both the answers they are coming same, means we can either perform addition first followed by subtraction or we can do subtraction first followed by addition.

same goes with multiplication and division too. that is we can multiply the numbers first followed by division and vice versa.

let us see an example for this too 

hope this small step is clear to you. yippieee!!!!! we have done it so easily.now many of you must be thinking if both the operators are of equal ranks then how should we go about to perform these operations??

let me tell you a simple RULE ----- 

always go from "LEFT to RIGHT"

                                         

let us see with an example

                            6÷2×6 

                 solve this by left to right 

                ✅           6÷2=3

                            3×6=18   ---1

          

             now solve it by right to left

                        

               ❌              2×6=12

                             6÷12=0.5   ---2

here we can see that both the answers are different for same question so we need to keep this in mind that no matter what we have to solve the question from LEFT to RIGHT only.

we have understand it till here,lets solve some questions to have good practice.------>  WORKSHEET LEVEL1

 i am doing one for you

                  ex:-  2×6+6......here in this which part is calculated first? 

as per BODMAS of  both the operators, "multiplication"is performed before"addition".   

 so                    2×6+6  =  12+6  =  18.

also solve these questions  🠚      1) 12−8+2  

                                                  2) 12+8×2

                                                  3) 15−3×4

                                                  4) 8÷2×4

LEVEL1 SUCCESSFUL

now we will see some more questions which include bracket and indices

    ex:-  (15−3)×4

here if we look in BODMAS 1st word is 'B' that means first bracket will be solved( i.e; subtraction of 15 and 3) followed by multiplication with 4. so lets solved it

           (15-3) =12 ===>12×4 = 48 

   ex:-  (12+8)×2

           (12+8) = 20 ===>20×2 =40

lets us take one more example

    ex:- (3+5)×6−2×(3×4)

here we have two brackets so we can simultaneously solve both the brackets i.e;  step 1 ->  (3+5) = 8      and      (3×4) = 12

             8×6−2×12  

now after bracket as there is no indices so next priority is multiplication/division. here two multiplications are given so we can solve both simultaneously.

                     step 2 ->   8×6 = 48      and       2×12 = 24

                     step 3 ->     48-24 

now we will see an other example

    ex:- (3²+5)×4−4

here in this question as per BODMAS we will solve bracket first but within bracket also there are two operators one is square and other is addition. square is one of the indices.so again within the bracket we will apply BODMAS. according to that indices should be solved first and then addition.

          step 1  -> (3²+5) ==> 3×3+5 = 9+5 = 14 

          step 2 -> 14×4−4 ==> 56-4 =52

I hope these examples would have helped you.for more practice solve this WORKSHEET LEVEL2. 

Understood till here?

let us see some more complex examples to ace this concept.

===>  ((15−3)×2÷ 25% of 12)

         

          in this question we will first solve bracket

          (15-3)=12

now we will solve percentage (as percentage is same rank as of indices)

           25% of 12 = 3   if you don't know how to calculate percentage you can refer PERCENTAGE.

        let us rewrite it

        12×2÷3

        now for this, we will go for left to right (multiplication and division are of same rank)

        24÷3 = 8

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